0=-16x^2+192x+1728

Solution for 0=-16x^2+192x+1728 equation:

0=-16x^2+192x+1728

We move all terms to the left:

0-(-16x^2+192x+1728)=0

We add all the numbers together, and all the variables

-(-16x^2+192x+1728)=0

We get rid of parentheses

16x^2-192x-1728=0

a = 16; b = -192; c = -1728;
Δ = b2-4ac
Δ = -1922-4·16·(-1728)
Δ = 147456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{147456}=384$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-192)-384}{2*16}=\frac{-192}{32}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-192)+384}{2*16}=\frac{576}{32}
=18
$